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" Take half a drachm of nitrate of lead and dissolve in a pint or more of boiling water. Dissolve two drachms of common salt in a pail or bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will... "
The Dental Practitioner - Page 32
1883
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Medical News and Abstract, Volumes 33-34

Medicine - 1875 - 420 pages
...a pint or more of boiling water, then dissolve two drachms of common salt in a bucket of water, and pour the two solutions together ; allow the sediment to subside. The clear supernatent fluid will be a saturated solution of chloride of lead. A cloth dipped in this solution...
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American Journal of Dental Science

Dentistry - 1876 - 606 pages
...a pint or more of boiling water, then dissolve two drachms of common salt in a bucket of water, and pour the two solutions together ; allow the sediment to subside. The clear supernatent fluid will be a saturated solution of chloride of lead. A cloth dipped in this solution...
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A manual of family medicine for India, Issue 272

sir William James Moore - 1877 - 640 pages
...sufficient to make nearly 400 gallons of fluid, so that it is also remarkably cheap. To prepare it for use, take half a drachm of nitrate of lead, and dissolve in a pint or more of boiling water. Then dissolve two drachms of common salt in a bucket of water. Pour the two solutions together, and...
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The Year-book of Facts in Science and Art

Science - 1877 - 388 pages
...purposes half a drachm of nitrate of lead, dissolve it in a pint or more of boiling water, dissolve about two drachms of common salt in a pail or bucket of water, pour the two solutions together, and allow the sediment to settle. A cloth dipped in this liquid and hung up will sweeten a foetid atmosphere...
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The Little gleaner, Volumes 5-6

1883 - 684 pages
...follows — take a halfdrachm of nitrn te of lead, and dissolve in a pint or more of boilinsr water. Now dissolve two drachms of common salt in a pail or bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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Medical Record, Volume 20

George Frederick Shrady, Thomas Lathrop Stedman - Medicine - 1881 - 798 pages
...chloride of lead. It is inodorous, effective, and its cost very small. It may be prepared as follows : Take half a drachm of nitrate of lead and dissolve...bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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Sanitary Engineering, Volume 6

1881 - 328 pages
...chloride of lead. It is inodorous, effective, and its cost very small. It may be prepared as follows : — Take half a drachm of nitrate of lead and dissolve...bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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The exhibition record, a descriptive account of the principal exhibits ...

International health exhibition, 1884 - 1882 - 564 pages
...chloride of lead. It is inodorous, effective, and its cost very small. It maybe prepared as follows: — Take half a drachm of nitrate of lead and dissolve...bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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Philadelphia Medical Times, Volume 12

Medicine - 1882 - 934 pages
...chloride of lead. It is inodorous, effective, and its cost very small. It may be prepared as follows. Take half a drachm of nitrate of lead and dissolve...bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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The Medical Times and Register, Volume 12

Medicine - 1882 - 916 pages
...chloride of lead. It is inodorous, effective, and its cost very small. It may be prepared as follows. Take half a drachm of nitrate of lead and dissolve...bucket of water, pour the two solutions together, and allow the sediment to subside. The clear supernatant fluid will be a saturated solution of chloride...
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